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Topic Title: Attenuating AC signals Topic Summary: Can you use a voltage divider? Created On: 15 March 2012 11:06 AM Status: Post and Reply |
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 15 March 2012 11:06 AM
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Hi, apologies for asking such an easy question, however, I was wondering if you can use a voltage divider to attenuate AC signals as well as DC?
If yes, what are the advatages of using an attenuator chip over a crude voltage divider (if any)? Any and all help/information would be much appreciated... Thanks, Steve |
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15 March 2012 01:24 PM
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Have a look here:
https://www.circuitlab.com/circuit/5jj6sj/resistor_attenuator/ 
------------------------- Andy Fierman --------------------------- http://signality.co.uk --------------------------- |
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15 March 2012 01:57 PM
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What do you mean by an attenuator chip? Can you give an example?
------------------------- Andy Millar CEng MIET MCMI http://www.linkedin.com/in/millarandy |
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15 March 2012 03:59 PM
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Andy M, I was thinking about something such as IMS A-1612.
However the link Andy F provided was very clear and answered my question. Cheers Andy F. I knew it was an easy question just had one of those moments when you doubt yourself. Thanks for your help guys. Stephan |
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16 March 2012 08:46 AM
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Good stuff.
Just for info, this chip will be just a collection of resistors forming (effectively) a voltage divider, the advantage of a device like this is that all the resistors can be perfectly matched (possibly laser trimmed?) by the manufacturer, so it will be much more accurate than an attenuator built using off-the-shelf resistors. Often you don't need that much accuracy, or for a one-off you can hand select the resistors, but for high accuracy production volumes the chip is better. Cheers, Andy ------------------------- Andy Millar CEng MIET MCMI http://www.linkedin.com/in/millarandy |
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23 March 2012 07:44 AM
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what is the meaning of attenuate AC ???
---------------------- lalinguaarabapertutti.com Edited: 30 March 2012 at 07:54 AM by nicolsaaa |
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23 March 2012 09:04 AM
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Attenuate = make smaller.
AC = Alternating Current, in other words a varying voltage or current signal. As in: https://www.circuitlab.com/circuit/5jj6sj/resistor_attenuator/ ------------------------- Andy Fierman --------------------------- http://signality.co.uk --------------------------- |
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10 May 2013 04:04 PM
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Pardon me but there is some confusion here. If you wish to attenuate a CURRENT signal then you must use a current-divider. It is the same beastie as a voltage-divider except that you connect it back-to-front; i.e. the current-signal goes in at the tapping point and the attenuated signal is taken from across the entire circuit. You may have to add a padding resistor in series with the input to a variable attenuator to prevent short-circuiting the driver at minimum output.
The lower part of this divider shunts unwanted current from the i/p to the transistor. Ken Green I |
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10 May 2013 05:03 PM
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To illustrate Kens point, I have updated:
https://www.circuitlab.com/circuit/5jj6sj/resistor_attenuator/ to include an example of a current divider for attenuating currents as well as the original potential divider for attenuating voltages. ------------------------- Andy Fierman --------------------------- http://signality.co.uk --------------------------- |
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23 May 2013 06:10 AM
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Can potentiometer be an example of current divider.
Regards, Sandip Roy. |
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23 May 2013 08:41 AM
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Potentiometers are normally used as voltage dividers. But given a constant-current source, I can see a way to use one as a current divider.
Connect the AC source to the slider. Connect one end of the track to the AC sink. Connect the other end of the track, through the load, to the AC sink. (By "source" and "sink", I just mean the two ends of the current-limited AC supply) ------------------------- S P Barker BSc PhD MIET |
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23 May 2013 08:55 AM
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In my example on CircuitLab:
https://www.circuitlab.com/circuit/5jj6sj/resistor_attenuator/ you can visualise what ectophile is explaining by considering the "ac2" node at the junction of R5 and R6 as being the slider of the potentiometer and the grounded ends of R5 and R6 being each end of the potentiometer. If you run the simulation, you can see how the total current from the AC current source Iac1 is shared in inverse proportion to the values of R5 and R6. ------------------------- Andy Fierman --------------------------- http://signality.co.uk --------------------------- |
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Attenuating AC signals
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