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Topic Title: capacitors,dielectrics.......help me out Topic Summary: question on dielectric Created On: 16 November 2010 09:00 PM Status: Post and Reply |
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 16 November 2010 09:00 PM
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a capacitor is to be constructed so that its capacitance is 0.2micro farad and to take a p.d of 1.25kV across its terminals.The dilelectric is to be mica which after allowing a safety factor of 2 has a dielectric strenght of 50milliVolts per metre
a] find the thickness of the mica needed b] determine the area of the plate assuming its a two plate construction |
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17 November 2010 09:36 AM
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What equations have you been given in the lesson notes?
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17 November 2010 01:54 PM
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unfortunately we the lecturee hasnt bn forthcoming....otherwise from study Q=CV....C=[Relative pemeativity*d]/A.........now i saw a formula which talks of capacitance per unit area which is C=E/D.........am not sure what E stands for in this equation............bt C is capacitance and D is plates separtion =thickness of dielectric
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18 November 2010 08:46 AM
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It would be best to consult the lecturer if you feel he has not prepared you well enough for your homework. Or you could get a text book out of the library.
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19 November 2010 04:50 PM
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Hi,
This is reasonably straight forward. Firstly, I'm quite sure the dielectric strength of mica is not 50 mV/m. It is more like 50MV/m so there may be a slight mistake there. To find thickness use: E=V/d E = 50MV/m, V = 1.25 kV For the area use, C= eps.A/d Use d from part a and find out what the rel. perm is for mica. Something like 7 I think. C is given in the question. Hope that helps. |
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