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 Topic Title: N+1 Redundant setup help Topic Summary: Battery design for DC Power system.. Created On: 04 November 2010 12:39 PM Status: Read Only Linear : Threading : Single : Branch
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 04 November 2010 12:39 PM amarlama Posts: 4 Joined: 21 September 2010 Hi All, I have a problem which may have a simple solution but I just wanted to make sure that I was going the right way. I have a load which draws 40A of current at 48V. I am seting up battery banks which can provide power for 4 hours minimum. With all other factors, required battery capacity comes upto 388 Ahrs. I have 4 batteries (48V, 150A) in series to form a bank/string. So I will require minimum of 3 strings of batteries (450Ahrs) in pararllel to meet the requirement. Now the question is.... For N+1 setup, can I just have 4 strings of batteries in parallel to full fill the required redundancy set up or will I need 6 strings in parallel (i.e. 3strings+3strings). I am thinking its 6 strings but just wanted to make sure. Hope someone could help me with this confusion. Thank you in Advance. Amar. Battery Set up |---------------0 Load 0----------------------| | | |---B1-----------B2--------B3--------B4----| | | |---B1-----------B2--------B3--------B4----| | | |---B1-----------B2--------B3--------B4----| ........... ...... ... Edited: 04 November 2010 at 01:16 PM by amarlama 04 November 2010 01:14 PM pauldixon Posts: 1 Joined: 09 January 2004 If you are wanting redundancy to manage single fault condition, then you need only one more string of cells than required to meet normal use current requirements - the redundancy is to cover the case of any one cell (string of cells) going open-circuit. So with 3 strings required by design (N = 3), you would need 4 (N+1) to comply with the redundancy requirement. 04 November 2010 01:21 PM amarlama Posts: 4 Joined: 21 September 2010 Originally posted by: pauldixon If you are wanting redundancy to manage single fault condition, then you need only one more string of cells than required to meet normal use current requirements - the redundancy is to cover the case of any one cell (string of cells) going open-circuit. So with 3 strings required by design (N = 3), you would need 4 (N+1) to comply with the redundancy requirement. My initial thoughts were similar, its just I got the second thought of assuming N being 3 strings and for back up similar second set up hence requiring 6 strings. But its making more sense to have 4 strings for N+1.. then 6 strings or else it would have been 2N setup.. Thanks for the help Paul.
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