IET logo
 
IET
Decrease font size
Increase font size
Topic Title: Formula Factor
Topic Summary: Anyone know what 0.48 represents?
Created On: 31 December 2012 02:20 PM
Status: Post and Reply
Linear : Threading : Single : Branch
Search Topic Search Topic
Topic Tools Topic Tools
View similar topics View similar topics
View topic in raw text format. Print this topic.
 31 December 2012 02:20 PM
User is offline View Users Profile Print this message



Sagalout

Posts: 2
Joined: 13 April 2011

In 5.1.2 of appendix 4 page 309 (BS 7671) there are details of the different formulas for calculating grouping factors, and equation 4 has a factor of 0.48 Ib squared (sorry can't seem to add a superscript 2), does anyone know what this 0.48 represents? I have quite a good library of text books and some of them refer to this formula but not one states where this factor is derived from. Neither can I find it on the web.

Cheers SL
 31 December 2012 03:21 PM
User is offline View Users Profile Print this message



alanblaby

Posts: 394
Joined: 09 March 2012

I think it will be a correction factor in the equation, there are examples of its use in the IEE Electrical Installation Design Guide - calculations for electricians, p.49.

From a quick read, using the equation will allow grouped cables to be smaller, as it is very unlikely for them all to be subject to overload at the same time.
The example there shows Ib divided into the Cg.. factors, and giving a resulting It of 27.5A, the '0.48' equation gives a result of 24.7A for the same circuits, with the result being a cable capable of carrying 27.5A is needed, the larger result being the one required.

Comparing the results from Equation 2, and 3&4, Eq2 gives a current of 33.3A, Eq3&4 27.5A, so a smaller cable size is available if you do the longer calculations.

So, being as there is a lot of squaring and square root in the equation, a correction factor would be my best assumption.
 31 December 2012 08:02 PM
User is offline View Users Profile Print this message



Jaymack

Posts: 4754
Joined: 07 April 2004

Originally posted by: Sagalout
In 5.1.2 of appendix 4 page 309 (BS 7671) there are details of the different formulas for calculating grouping factors, and equation 4 has a factor of 0.48 Ib squared (sorry can't seem to add a superscript 2), does anyone know what this 0.48 represents?

The second part of the equation, looks like that for the calculation of an RMS value for heating effect. It could be a fudge factor from thermal modelling, as mathematicians are prone to do. But who would use the calculations in the practical sense, when tables are available?

Regards
 02 January 2013 09:34 AM
User is offline View Users Profile Print this message



Sagalout

Posts: 2
Joined: 13 April 2011

Hi Gents

Thanks for your views on this and confirming basically what I thought anyway. My reason for inquiring was purely curiosity as I was a bit bored over the Xmas period. Sad I know!

Cheers and happy new year SL
 02 January 2013 07:15 PM
User is offline View Users Profile Print this message



Chris123

Posts: 325
Joined: 08 February 2010

Id say its a Nusselt Number, Look up Churchill, Prandt, Rayleigh.

If you think you were bored, you will be
 04 January 2013 08:44 AM
User is offline View Users Profile Print this message



hpcompaq

Posts: 78
Joined: 27 September 2007

Hello.

1.45 is the current causing effective operation of the protective device (see 433.1.1). In the derivation of the appendix 4 formula 1.45 ends up being squared and appears in the denominator, this is the same as multiplying by [1 divided by 1.45 squared] which equals 0.4756.... which rounds up to 0.48.
Statistics

See Also:



FuseTalk Standard Edition v3.2 - © 1999-2014 FuseTalk Inc. All rights reserved.