
RTS PROJECT MANAGER (Future Networks focus)
 Perth, Perth and Kinross
 SALARY £36,923 to £48,767 (SSE8) DEPENDING ON SKILLS AND EXPERIENCE
The RTS Delivery team has responsibility for the systems deployed in substations and other electrical plant locations and the operational...
 Recruiter: SSE

Multiskilled Maintenance Engineer/Technician
 Slough, Berkshire
 £3341k per annum + comprehensive benefits
Your key challenge will be to get under the skin (or wrapper) of a problem and not rest until you've solved it – right down to the root cause.
 Recruiter: Mars Chocolate

Head of Technical – Electricity Networks
 London or Glasgow
 £74,000  £82,000 (London) or £68,400  £76,200 (Glasgow)
Take a leading technical role in a variety of areas such as the development and delivery of price controls and competitive tender regimes for networks
 Recruiter: Ofgem
IET 
search :
help :
home


Latest News:


Topic Title: Formula Factor Topic Summary: Anyone know what 0.48 represents? Created On: 31 December 2012 02:20 PM Status: Post and Reply 
Linear : Threading : Single : Branch 
Search Topic

Topic Tools

31 December 2012 02:20 PM


In 5.1.2 of appendix 4 page 309 (BS 7671) there are details of the different formulas for calculating grouping factors, and equation 4 has a factor of 0.48 Ib squared (sorry can't seem to add a superscript 2), does anyone know what this 0.48 represents? I have quite a good library of text books and some of them refer to this formula but not one states where this factor is derived from. Neither can I find it on the web.
Cheers SL 



31 December 2012 03:21 PM


I think it will be a correction factor in the equation, there are examples of its use in the IEE Electrical Installation Design Guide  calculations for electricians, p.49.
From a quick read, using the equation will allow grouped cables to be smaller, as it is very unlikely for them all to be subject to overload at the same time. The example there shows Ib divided into the Cg.. factors, and giving a resulting It of 27.5A, the '0.48' equation gives a result of 24.7A for the same circuits, with the result being a cable capable of carrying 27.5A is needed, the larger result being the one required. Comparing the results from Equation 2, and 3&4, Eq2 gives a current of 33.3A, Eq3&4 27.5A, so a smaller cable size is available if you do the longer calculations. So, being as there is a lot of squaring and square root in the equation, a correction factor would be my best assumption. 



31 December 2012 08:02 PM


In 5.1.2 of appendix 4 page 309 (BS 7671) there are details of the different formulas for calculating grouping factors, and equation 4 has a factor of 0.48 Ib squared (sorry can't seem to add a superscript 2), does anyone know what this 0.48 represents? The second part of the equation, looks like that for the calculation of an RMS value for heating effect. It could be a fudge factor from thermal modelling, as mathematicians are prone to do. But who would use the calculations in the practical sense, when tables are available? Regards 



02 January 2013 09:34 AM


Hi Gents
Thanks for your views on this and confirming basically what I thought anyway. My reason for inquiring was purely curiosity as I was a bit bored over the Xmas period. Sad I know! Cheers and happy new year SL 



02 January 2013 07:15 PM


Id say its a Nusselt Number, Look up Churchill, Prandt, Rayleigh.
If you think you were bored, you will be 



04 January 2013 08:44 AM


Hello.
1.45 is the current causing effective operation of the protective device (see 433.1.1). In the derivation of the appendix 4 formula 1.45 ends up being squared and appears in the denominator, this is the same as multiplying by [1 divided by 1.45 squared] which equals 0.4756.... which rounds up to 0.48. 


IET
» Wiring and the regulations
»
Formula Factor

Topic Tools

FuseTalk Standard Edition v3.2  © 19992016 FuseTalk Inc. All rights reserved.