Hi,

Have another question! Sorry about posting so many recently. I've got a bit of coursework that I have to do and would like to know if anyone could help me.

A capacitor of 22uF is connected in parallel with a resistor of 75 ohms to a 100v supply at 150Hz. Find the current flowing in the resistive branch and the capacitive branch.

I believe that for the capacitive branch; I = U / Xc. Find out inductive capacitance and then sub into above equation.

Resistive branch; I = U / R.

Thanks for the help.

Something looks wrong to me on the capacitor side. With the equation you've got, if you increase the value of 'c', then the current 'I' would drop. That's not what would happen.

IIRC, for a capacitor, the impedance is X = 1 / (2 * pi * f * c).

So I = U / X = U * (2 * pi * f * c).

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S P Barker BSc PhD MIET

No, the OP is quite correct.

When he's written Xc, that means the capacitive reactance.
You've taken it to mean XC, or X * C, which would be the reactance multiplied by the capacitance. That would be wrong.

I took "Xc" to be simply the impedance due to the capacitor (although I'm not sure there's anything inductive about it). Xc = 1/(2πfC)
- Andy.

If you put it that way, then it is right. I was trying to read more into it.

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S P Barker BSc PhD MIET

Sorry I meant capacitive reactance! Thanks for the help all.